$A$ screw gauge has $50$ divisions on its circular scale. The circular scale is $4$ units ahead of the pitch scale marking,prior to use. Upon one complete rotation of the circular scale,a displacement of $0.5\, mm$ is noticed on the pitch scale. The nature of zero error involved,and the least count of the screw gauge,are respectively
- ANegative,$2\, \mu m$
- BPositive,$10\, \mu m$
- CPositive,$0.1\, \mu m$
- DPositive,$0.1\, mm$
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