A ray of light travelling in a transparent me | vedclass

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Question

(C) For total internal reflection to occur,the angle of incidence $i$ must be greater than the critical angle $C$,i.e.,$i > C$.This implies $\sin i >

Vedclass · Accepted Answer

$1.50$

Vedclass · Answer

(C) For total internal reflection to occur,the angle of incidence $i$ must be greater than the critical angle $C$,i.e.,$i > C$.This implies $\sin i > \sin C$.We know that $\sin C = \frac{1}{n}$,where $n$ is the refractive index of the medium with respect to air.Substituting this into the inequality,we get $\sin i > \frac{1}{n}$,which simplifies to $n > \frac{1}{\sin i}$.Given the angle of incidence $i = 45^{\circ}$,we have:$n > \frac{1}{\sin 45^{\circ}}$$n > \frac{1}{1/\sqrt{2}}$$n > \sqrt{2} \approx 1.414$.Among the given options,only $1.50$ is greater than $1.414$. Therefore,the correct option is $C$.

$A$ ray of light travelling in a transparent medium of refractive index $n$ falls on a surface separating the medium from air at an angle of incidence of $45^{\circ}$. For which of the following values of $n$ can the ray undergo total internal reflection?

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