A quantity f is given by f = sqrt{frac{hc^5}{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The dimensions of the constants are:$[h] = M^1 L^2 T^{-1}$$[c] = L^1 T^{-1}$$[G] = M^{-1} L^3 T^{-2}$Substituting these into the expression for $f

Vedclass · Accepted Answer

Energy

Vedclass · Answer

(C) The dimensions of the constants are:$[h] = M^1 L^2 T^{-1}$$[c] = L^1 T^{-1}$$[G] = M^{-1} L^3 T^{-2}$Substituting these into the expression for $f$:$[f] = \sqrt{\frac{(M^1 L^2 T^{-1}) 	imes (L^1 T^{-1})^5}{M^{-1} L^3 T^{-2}}}$$[f] = \sqrt{\frac{M^1 L^2 T^{-1} 	imes L^5 T^{-5}}{M^{-1} L^3 T^{-2}}}$$[f] = \sqrt{\frac{M^1 L^7 T^{-6}}{M^{-1} L^3 T^{-2}}}$$[f] = \sqrt{M^{1-(-1)} L^{7-3} T^{-6-(-2)}}$$[f] = \sqrt{M^2 L^4 T^{-4}}$$[f] = M^1 L^2 T^{-2}$The dimension $M^1 L^2 T^{-2}$ corresponds to the dimension of Energy.

$A$ quantity $f$ is given by $f = \sqrt{\frac{hc^5}{G}}$,where $c$ is the speed of light,$G$ is the universal gravitational constant,and $h$ is Planck's constant. The dimension of $f$ is that of:

Similar Questions

Given that $v$ is speed,$r$ is the radius,and $g$ is the acceleration due to gravity. Which of the following is dimensionless?

If velocity $(V)$,force $(F)$ and time $(T)$ are chosen as fundamental quantities,then the dimensions of energy are:

The dimension of stopping potential $V_{0}$ in the photoelectric effect in terms of Planck's constant $h$,speed of light $c$,gravitational constant $G$,and ampere $A$ is:

If $E$,$L$,$m$ and $G$ denote the quantities as energy,angular momentum,mass and constant of gravitation respectively,then the dimensions of $P$ in the formula $P = EL^2 m^{-5} G^{-2}$ are

The potential energy of a point particle is given by the expression $V(x) = -\alpha x + \beta \sin(x / \gamma)$. $A$ dimensionless combination of the constants $\alpha, \beta$ and $\gamma$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module