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Question

(A) Given,Area $A = (100 \pm 0.2) \, m^2$.Since the park is a square,$A = l^2$,where $l$ is the side length.Calculating the side length: $l = \sqrt{A}

Vedclass · Accepted Answer

$(10 \pm 0.01)$

Vedclass · Answer

(A) Given,Area $A = (100 \pm 0.2) \, m^2$.Since the park is a square,$A = l^2$,where $l$ is the side length.Calculating the side length: $l = \sqrt{A} = \sqrt{100} = 10 \, m$.Using the error propagation formula for $A = l^2$,we have $\frac{\Delta A}{A} = 2 \frac{\Delta l}{l}$.Substituting the given values: $\frac{0.2}{100} = 2 	imes \frac{\Delta l}{10}$.Solving for $\Delta l$: $\Delta l = \frac{0.2 	imes 10}{100 	imes 2} = \frac{2}{200} = 0.01 \, m$.Therefore,the side of the park is $(10 \pm 0.01) \, m$.

$A$ public park,in the form of a square,has an area of $(100 \pm 0.2) \, m^2$. The side of the park is ......... $m$.

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