A proton moving with a velocity, $2.5 \times {10^7}\,m/s$, enters a magnetic field of intensity $2.5\,T$ making an angle ${30^o}$ with the magnetic field. The force on the proton is
A proton moving with a velocity, $2.5 \times {10^7}\,m/s$, enters a magnetic field of intensity $2.5\,T$ making an angle ${30^o}$ with the magnetic field. The force on the proton is
- A
$3 \times {10^{ - 12}}\,N$
- B
$5 \times {10^{ - 12}}\,N$
- C
$6 \times {10^{ - 12}}\,N$
- D
$9 \times {10^{ - 12}}\,N$
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