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Question

(A) The force on a charged particle moving with velocity $v$ in the presence of electric field $E$ and magnetic field $B$ is given by the Lorentz forc

Vedclass · Accepted Answer

$E=0, B 
eq 0$

Vedclass · Answer

(A) The force on a charged particle moving with velocity $v$ in the presence of electric field $E$ and magnetic field $B$ is given by the Lorentz force equation: $F = q(E + v 	imes B)$.For the velocity to remain constant,the net force $F$ must be zero.$(i)$ If $E=0$ and $B 
eq 0$,the proton can move parallel or anti-parallel to the magnetic field $B$. In this case,the magnetic force $F_m = q(v 	imes B) = 0$ because the angle between $v$ and $B$ is $0^{\circ}$ or $180^{\circ}$. Thus,the velocity remains constant.$(ii)$ If $E 
eq 0$ and $B 
eq 0$,the electric force $F_e = qE$ and magnetic force $F_m = q(v 	imes B)$ can be equal and opposite,such that $F_e + F_m = 0$. This is the principle of a velocity selector.Since the question asks what the region *may* have,and option $A$ $(E=0, B 
eq 0)$ is a valid condition where the proton experiences no force,it is a correct possibility.

$A$ proton moving with a constant velocity passes through a region of space without any change in its velocity. If $E$ and $B$ represent the electric and magnetic fields respectively,this region may have:

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