$A$ proton,an electron,and an alpha particle have the same kinetic energies. Their de-Broglie wavelengths will be compared as:

• A
  $\lambda_{e} > \lambda_{p} > \lambda_{\alpha}$
• B
  $\lambda_{\alpha} < \lambda_{p} < \lambda_{e}$
• C
  $\lambda_{p} < \lambda_{e} < \lambda_{\alpha}$
• D
  $\lambda_{p} > \lambda_{e} > \lambda_{\alpha}$