A point object is placed at a distance of 30 | vedclass

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Question

(D) Using the mirror formula:$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$Given:Object distance $u = -30 \, cm$ (by sign convention)Focal length $f = +30

Vedclass · Accepted Answer

$15 \, cm$ behind the mirror

Vedclass · Answer

(D) Using the mirror formula:$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$Given:Object distance $u = -30 \, cm$ (by sign convention)Focal length $f = +30 \, cm$ (for a convex mirror)Substituting the values:$\frac{1}{v} + \frac{1}{-30} = \frac{1}{30}$$\frac{1}{v} = \frac{1}{30} + \frac{1}{30}$$\frac{1}{v} = \frac{2}{30}$$\frac{1}{v} = \frac{1}{15}$$v = +15 \, cm$Since the value of $v$ is positive,the image is formed at $15 \, cm$ behind the mirror.

$A$ point object is placed at a distance of $30 \, cm$ from a convex mirror of focal length $30 \, cm$. The image will form at

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