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(B) The magnification $m$ is given by the ratio of the height of the image to the height of the object,which is $m = \frac{h_i}{h_o} = \frac{1}{5}$.Si

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Convex mirror

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(B) The magnification $m$ is given by the ratio of the height of the image to the height of the object,which is $m = \frac{h_i}{h_o} = \frac{1}{5}$.Since the image is erect,the magnification is positive $(m = +0.2)$.$A$ plane mirror always produces an image of the same size $(m = 1)$,so it is not a plane mirror.$A$ concave mirror can produce an erect image only when the object is placed between the pole and the focus,but in that case,the image is always magnified $(m > 1)$.$A$ convex mirror always forms a virtual,erect,and diminished image for all positions of the object.Therefore,the mirror must be a convex mirror.

$A$ boy stands straight in front of a mirror at a distance of $30 \ cm$ away from it. He sees his erect image whose height is $\frac{1}{5}$ of his real height. The mirror he is using is

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