A pen was sold for a certain sum and there wa | vedclass

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Question

Let $CP$ of pen be $Rs.\,x$

and $SP$ be $Rs.\, y$

Initially at loss of $20 \%$

$\Rightarrow \frac{20}{100}=\frac{x-y}{x} \Rightarrow \frac{1}

Vedclass · Accepted Answer

no profit, no loss

Vedclass · Answer

Let $CP$ of pen be $Rs.\,x$

and $SP$ be $Rs.\, y$

Initially at loss of $20 \%$

$\Rightarrow \frac{20}{100}=\frac{x-y}{x} \Rightarrow \frac{1}{5} x=x-y \Rightarrow \quad y=\frac{4}{5} x$ $...(i)$

Now if $y$ would change to $Rs.$ $(y + 12),$ then profit becomes $30\%$

$\Rightarrow \frac{30}{100}=\frac{y+12-x}{x} \Rightarrow \frac{3}{10}=\frac{\frac{4}{5} x+12-x}{x}$

$\Rightarrow x=$ $Rs. 24$ $...(ii)$

$y=\operatorname{Rs} \frac{96}{5}$ or $\operatorname{Rs} .19 .2$ $...(iii)$

$\%$ profit now if $y$ becomes $Rs.$ $(y+4.8)$

$\Rightarrow \quad \%$ profit $=\frac{ SP - CP }{ CP } 	imes 100=\frac{ Rs \cdot( y +4.8)-24}{24} 	imes 100$

$=\frac{\operatorname{Rs} \cdot(19 \cdot 2+4 \cdot 8)-24}{24} 	imes 100=0 \%$

A pen was sold for a certain sum and there was a loss of $20 \% .$ Had it been sold for $Rs.\, 12$ more, there would have been a gain of $30 \% .$ What would be the profit if the pen was sold for $Rs.\, 4.80$ more than what it was sold for? (in $\%$)

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