A shopkeeper cheats to the extent of 10 % whi | vedclass

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Question

The shopkeeper pays for $900$ $g$ instead of $1000$ $g$ while buying and sells the item weighing $900 gm$ for $1000 g$ or $1 kg$

$\operatorname{Gai

Vedclass · Accepted Answer

$21$

Vedclass · Answer

The shopkeeper pays for $900$ $g$ instead of $1000$ $g$ while buying and sells the item weighing $900 gm$ for $1000 g$ or $1 kg$

$\operatorname{Gain} \%=\frac{(100+\operatorname{common} gain \%)^{2}}{100}-100$

$=\left[\frac{(100+10)^{2}}{100}-100\right] \%$

$=\left[\frac{12100}{100}-100\right] \%=21 \%$

A shopkeeper cheats to the extent of $10 \%$ while buying as well as selling, by using false weights. His total gain is in $\%$

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