Mohit lost 18 % by selling a bicycle for Rs., | vedclass

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Question

Here, $S.P._1$ $=Rs. 1230, x=-18$

$S.P _{2}=Rs. 1600, y=?$

Using the formula,

$\frac{ S.P ._{1}}{100+x}=\frac{ S.P _{2}}{100+y}$

we get, $

Vedclass · Accepted Answer

$6 \frac{2}{3} \%$ gain

Vedclass · Answer

Here, $S.P._1$ $=Rs. 1230, x=-18$

$S.P _{2}=Rs. 1600, y=?$

Using the formula,

$\frac{ S.P ._{1}}{100+x}=\frac{ S.P _{2}}{100+y}$

we get, $\frac{1230}{100-18}=\frac{1600}{100+y}$

$\Rightarrow 100+y=\frac{1600 	imes 82}{1230}=106 \frac{2}{3} \Rightarrow y=6 \frac{2}{3} \% 6 \frac{2}{3} \%$

Thus, Mohit has a gain of $6 \frac{2}{3} \%$ by selling it for $Rs.1600.$

Mohit lost $18 \%$ by selling a bicycle for $Rs.\, 1230$. What percent shall he gain or loss by selling it for $Rs.\, 1600 ?$

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