A patient in a hospital is given soup daily i | vedclass

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Question

$(A)$ The bowl is cylindrical.Diameter of the base $= 7 \, cm$.Radius of the base $(r) = \frac{7}{2} \, cm = 3.5 \, cm$.Height $(h) = 4 \, cm$.Volume

Vedclass · Accepted Answer

$38.5 \, 	ext{litres}$

Vedclass · Answer

$(A)$ The bowl is cylindrical.Diameter of the base $= 7 \, cm$.Radius of the base $(r) = \frac{7}{2} \, cm = 3.5 \, cm$.Height $(h) = 4 \, cm$.Volume of soup in one bowl $= \pi r^2 h = \frac{22}{7} 	imes (3.5)^2 	imes 4 \, cm^3$.Volume $= \frac{22}{7} 	imes \frac{7}{2} 	imes \frac{7}{2} 	imes 4 \, cm^3 = 11 	imes 7 	imes 2 \, cm^3 = 154 \, cm^3$.Volume of soup for $250$ patients $= 250 	imes 154 \, cm^3 = 38500 \, cm^3$.Since $1000 \, cm^3 = 1 \, 	ext{litre}$, the total volume in litres $= \frac{38500}{1000} \, 	ext{litres} = 38.5 \, 	ext{litres}$.Thus, the hospital needs to prepare $38.5 \, 	ext{litres}$ of soup daily.

$A$ patient in a hospital is given soup daily in a cylindrical bowl of diameter $7 \, cm$. If the bowl is filled with soup to a height of $4 \, cm$, how much soup does the hospital have to prepare daily to serve $250$ patients?

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