Difficult
$A$ particle of unit mass undergoes one-dimensional motion such that its velocity varies according to $v(x) = \beta x^{-2n}$,where $\beta$ and $n$ are constants and $x$ is the position of the particle. The acceleration of the particle as a function of $x$ is given by:
- A$-2n \beta^2 x^{-2n-1}$
- B$-2n \beta^2 x^{-4n-1}$
- C$-2n \beta^2 x^{-2n+1}$
- D$-2n \beta^2 x^{-4n+1}$
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View SolutionLet us define a motion as $A$ when velocity is positive and increasing,$A^{-1}$ when velocity is negative and increasing,$R$ when velocity is positive and decreasing,and $R^{-1}$ when velocity is negative and decreasing. Now,match the following two columns for the given $s-t$ graph.
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