Consider the following nuclear reactions:
$I$. ${ }_{7}^{14} N +{ }_{2}^{4} He \longrightarrow{ }_{8}^{17} O + X$
$II$. ${ }_{4}^{9} Be +{ }_{2}^{4} H \longrightarrow{ }_{6}^{12} He +Y$
Then,
Consider the following nuclear reactions:
$I$. ${ }_{7}^{14} N +{ }_{2}^{4} He \longrightarrow{ }_{8}^{17} O + X$
$II$. ${ }_{4}^{9} Be +{ }_{2}^{4} H \longrightarrow{ }_{6}^{12} He +Y$
Then,
- [KVPY 2017]
- A
$X$ and $Y$ are both protons
- B
$X$ and $Y$ are both neutrons
- C
$X$ is a proton and $Y$ is a neutron
- D
$X$ is neutron and $Y$ is a proton
Similar Questions
Assertion: ${}_Z{X^A}$ undergoes a $2\alpha -$ decays, $2\beta -$ decays and $2\gamma - $ decays and the daughter product is ${}_{Z - 2}{X^{A - 8}}$
Reason : In $\alpha - $decays the mass number decreases by $4$ and atomic number decreases by $2$. In $2\beta - $ decays the mass number remains unchanged, but atomic number increases by $1$ only.
Assertion: ${}_Z{X^A}$ undergoes a $2\alpha -$ decays, $2\beta -$ decays and $2\gamma - $ decays and the daughter product is ${}_{Z - 2}{X^{A - 8}}$
Reason : In $\alpha - $decays the mass number decreases by $4$ and atomic number decreases by $2$. In $2\beta - $ decays the mass number remains unchanged, but atomic number increases by $1$ only.
- [AIIMS 2001]
The $\beta$-particles of a radioactive metal originate from
The $\beta$-particles of a radioactive metal originate from
- [KVPY 2015]
A nucleus of an element ${}_{84}{X^{202}}$ emits an $\alpha $-particle first, $\beta $ -particle next and then a gamma photon. The final nucleus formed has an atomic number
A nucleus of an element ${}_{84}{X^{202}}$ emits an $\alpha $-particle first, $\beta $ -particle next and then a gamma photon. The final nucleus formed has an atomic number
The particles emitted by radioactive decay are deflected by magnetic field. The particles will be
The particles emitted by radioactive decay are deflected by magnetic field. The particles will be
Alpha particles are
Alpha particles are
- [AIPMT 1999]