(B) The resistance of the galvanometer is $G = 50\,\Omega$.The series resistance connected to convert it into a voltmeter is $R = 5\,k\Omega = 5000\,\

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(B) The resistance of the galvanometer is $G = 50\,\Omega$.The series resistance connected to convert it into a voltmeter is $R = 5\,k\Omega = 5000\,\Omega$.The full-scale deflection current is $I_g = 4\,mA = 4 \times 10^{-3}\,A$.The maximum voltage $V$ that can be measured by the voltmeter is given by the formula $V = I_g(G + R)$.Substituting the values: $V = 4 \times 10^{-3}\,A \times (50\,\Omega + 5000\,\Omega)$.$V = 4 \times 10^{-3} \times 5050$.$V = 4 \times 5.05 = 20.2\,V$.Therefore,the maximum voltage that can be measured is close to $20\,V$.

Class 12 Physics Moving Charges and Magnetism The Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion

Medium

$A$ moving coil galvanometer has a resistance of $50\,\Omega$ and it indicates full-scale deflection at a current of $4\,mA$. $A$ voltmeter is constructed using this galvanometer and a $5\,k\Omega$ series resistance. The maximum voltage that can be measured using this voltmeter will be close to ......$V$.

JEE MAIN 2019 All JEE MAIN

A
$15$
B
$20$
C
$10$
D
$40$

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Moving Charges and Magnetism

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The Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion

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