The ratio of heats generated through shunt an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given,the ratio of heats generated through the shunt $(H_s)$ and galvanometer $(H_g)$ is $H_s : H_g = 7 : 5$.The resistance of the galvanometer is

Vedclass · Accepted Answer

$80$

Vedclass · Answer

(A) Given,the ratio of heats generated through the shunt $(H_s)$ and galvanometer $(H_g)$ is $H_s : H_g = 7 : 5$.The resistance of the galvanometer is $R_g = 112 \Omega$.Since the shunt and galvanometer are connected in parallel to form an ammeter,the potential difference $(V)$ across both is the same.The heat generated in a resistor is given by $H = \frac{V^2}{R} 	imes t$.Therefore,the ratio of heat generated is $\frac{H_s}{H_g} = \frac{V^2 / R_s}{V^2 / R_g} = \frac{R_g}{R_s}$.Given $\frac{H_s}{H_g} = \frac{7}{5}$,we have $\frac{R_g}{R_s} = \frac{7}{5}$.Substituting the value of $R_g = 112 \Omega$:$\frac{112}{R_s} = \frac{7}{5}$$R_s = \frac{112 	imes 5}{7}$$R_s = 16 	imes 5 = 80 \Omega$.Thus,the resistance of the shunt is $80 \Omega$.

The ratio of heats generated through shunt and galvanometer is $7: 5$ when they are connected to make an ammeter. If the resistance of the galvanometer is $112 \Omega$,then the resistance of the shunt is: (in $Omega$)

Similar Questions

The resistance of a galvanometer is $50\,\Omega$ and the current required to give full-scale deflection is $100\,\mu A$. In order to convert it into an ammeter for reading up to $10\,A$,it is necessary to put a resistance of:

$A$ galvanometer of resistance $G \ \Omega$ is shunted by a resistance $S \ \Omega$. To keep the main current in the circuit unchanged,the resistance to be connected in series with the galvanometer is

$A$ galvanometer of resistance $20 \,\Omega$ is to be converted into an ammeter of range $1 \, A$. If a current of $1 \, mA$ produces full scale deflection,the shunt required for the purpose is ................ $\Omega $.

Only $4 \%$ of the total current in the circuit passes through a galvanometer. If the resistance of the galvanometer is $G$,then the shunt resistance connected to the galvanometer is:

In a galvanometer,the deflection becomes one half when the galvanometer is shunted by a $20\,\Omega$ resistor. The galvanometer resistance is ............... $\Omega$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module