The sensitivity of a moving coil galvanometer is inversely proportional to

  • A
    current it measures.
  • B
    number of turns in the coil.
  • C
    magnetic induction of the horse shoe magnet.
  • D
    torsional constant of the phosphor bronze suspension wire.

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$A$ voltmeter essentially consists of

$A$ maximum current of $0.5 \ mA$ can pass through a galvanometer of resistance $15 \ \Omega$. The resistance to be connected in series to the galvanometer to convert it into a voltmeter of range $0-10 \ V$ is (in $Omega$)

The sensitivity of a tangent galvanometer is increased if

In an ammeter,$0.25 \%$ of the main current passes through the galvanometer. If the resistance of the galvanometer is $G$,the resistance of the ammeter will be:

$A$ galvanometer has a resistance of $7\,\Omega$ and gives a full-scale deflection for a current of $1.0\,A$. How will you convert it into a voltmeter of range $10\,V$?

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