A metallic spherical shell has an inner radius $R_1$ and outer radius $R_2$. A charge $Q$ is placed at the centre of the spherical cavity. What will be surface charge density on the inner surface
$\frac{Q}{{4\pi R_1^2}}$
$ - \frac{Q}{{4\pi R_1^2}}$
$\frac{Q}{{4\pi R_2^2}}$
$ - \frac{Q}{{4\pi R_2^2}}$
For a spherical shell
A solid conducting sphere of radius $a$ has a net positive charge $2Q$. A conducting spherical shell of inner radius $b$ and outer radius $c$ is concentric with the solid sphere and has a net charge $-Q$. The surface charge density on the inner and outer surfaces of the spherical shell will be
Charges $Q, 2Q$ and $-Q$ are given to three concentric conducting shells $A, B$ and $C$ respectively as shown the ratio of charges on inner and outer surfaces of shell $C$ will be
Two metal spheres, one of radus $R$ and the other of radius $2 R$ respectively have the same surface charge density $\sigma$. They are brought in contact and separated. What will be the new surface charge densities on them?
If $q$ is the charge per unit area on the surface of a conductor, then the electric field intensity at a point on the surface is