A mass $m$ is suspended from the two coupled springs connected in series. The force constant for springs are ${K_1}$ and ${K_2}$. The time period of the suspended mass will be
$T = 2\pi \sqrt {\left( {\frac{m}{{{K_1} + {K_2}}}} \right)} $
$T = 2\pi \sqrt {\left( {\frac{m}{{{K_1} + {K_2}}}} \right)} $
$T = 2\pi \sqrt {\left( {\frac{{m({K_1} + {K_2})}}{{{K_1}{K_2}}}} \right)} $
$T = 2\pi \sqrt {\left( {\frac{{m{K_1}{K_2}}}{{{K_1} + {K_2}}}} \right)} $
On a smooth inclined plane, a body of mass $M$ is attached between two springs. The other ends of the springs are fixed to firm supports. If each spring has force constant $K$, the period of oscillation of the body (assuming the springs as massless) is
A particle executes $SHM$ with amplitude of $20 \,cm$ and time period is $12\, sec$. What is the minimum time required for it to move between two points $10\, cm$ on either side of the mean position ..... $\sec$ ?
Figure $(a)$ shows a spring of force constant $k$ clamped rigidly at one end and a mass $m$ attached to its free end. A force $F$ applied at the free end stretches the spring. Figure $(b)$ shows the same spring with both ends free and attached to a mass $m$ at etther end. Each end of the spring in Figure $( b )$ is stretched by the same force $F.$
$(a)$ What is the maximum extension of the spring in the two cases?
$(b)$ If the mass in Figure $(a)$ and the two masses in Figure $(b)$ are released, what is the period of oscillation in each case?
A spring is stretched by $0.20\, m$, when a mass of $0.50\, kg$ is suspended. When a mass of $0.25\, kg$ is suspended, then its period of oscillation will be .... $\sec$ $(g = 10\,m/{s^2})$
Force constant of a spring is $K$ . If half part is detached then force constant of the remaining spring will be