A man starts repaying a loan with a first ins | vedclass

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(A) The first installment of the loan is $a = 100$.The increase in the installment every month is the common difference $d = 5$.The sequence of instal

Vedclass · Accepted Answer

$Rs. 245$

Vedclass · Answer

(A) The first installment of the loan is $a = 100$.The increase in the installment every month is the common difference $d = 5$.The sequence of installments forms an Arithmetic Progression $(A.P.)$: $100, 105, 110, \dots$The formula for the $n^{th}$ term of an $A.P.$ is $a_n = a + (n - 1)d$.For the $30^{th}$ installment,$n = 30$:$a_{30} = 100 + (30 - 1) 	imes 5$$a_{30} = 100 + 29 	imes 5$$a_{30} = 100 + 145$$a_{30} = 245$Thus,the amount to be paid in the $30^{th}$ installment is $Rs. 245$.

$A$ man starts repaying a loan with a first installment of $Rs. 100$. If he increases the installment by $Rs. 5$ every month,what amount will he pay in the $30^{th}$ installment?

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