A magnet is moved in the direction indicated | vedclass

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(C) According to Lenz's law,the direction of the induced current is such that it opposes the change in magnetic flux that produced it.$1$. For coil $A

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$A$ to $B$ and $D$ to $C$

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(C) According to Lenz's law,the direction of the induced current is such that it opposes the change in magnetic flux that produced it.$1$. For coil $AB$: The North pole $(N)$ of the magnet is moving away from coil $AB$. To oppose this,the face of the coil near the magnet must act as a South pole $(S)$. This requires the current to flow in a clockwise direction when viewed from the magnet's side,which corresponds to the current flowing from $A$ to $B$ in the wire.$2$. For coil $CD$: The South pole $(S)$ of the magnet is moving towards coil $CD$. To oppose this,the face of the coil near the magnet must act as a South pole $(S)$. This requires the current to flow in a clockwise direction when viewed from the magnet's side,which corresponds to the current flowing from $D$ to $C$ in the wire.Therefore,the induced current flows from $A$ to $B$ and $D$ to $C$.

$A$ magnet is moved in the direction indicated by an arrow between two coils $AB$ and $CD$ as shown in the figure. The direction of the induced current in the coils is

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