A magnet is brought towards a coil (i) speedi | vedclass

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(B) According to Faraday's law of electromagnetic induction, the induced $e.m.f.$ $(\varepsilon)$ is given by $\varepsilon = - \frac{d\phi}{dt}$. Sinc

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More in first case / Equal in both cases

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(B) According to Faraday's law of electromagnetic induction, the induced $e.m.f.$ $(\varepsilon)$ is given by $\varepsilon = - \frac{d\phi}{dt}$. Since the speed is higher in the first case, the rate of change of magnetic flux $(\frac{d\phi}{dt})$ is greater, resulting in a higher induced $e.m.f.$The induced charge $(q)$ is given by $q = \int I \, dt = \int \frac{\varepsilon}{R} \, dt = \frac{1}{R} \int \frac{d\phi}{dt} \, dt = \frac{\Delta\phi}{R}$.Since the total change in magnetic flux $(\Delta\phi)$ and the resistance of the coil $(R)$ remain the same in both cases, the induced charge is equal in both cases.

$A$ magnet is brought towards a coil $(i)$ speedily and $(ii)$ slowly. What will be the induced $e.m.f.$ and induced charge, respectively?

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