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(B) $1$. The magnetic field $B$ due to a long straight current-carrying wire at a distance $r$ is given by $B = \frac{\mu_0 I}{2\pi r}$.$2$. As the ri

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induced current in the coil is anticlockwise.

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(B) $1$. The magnetic field $B$ due to a long straight current-carrying wire at a distance $r$ is given by $B = \frac{\mu_0 I}{2\pi r}$.$2$. As the ring falls towards the wire, the distance $r$ decreases, which means the magnetic flux $\phi$ linked with the ring increases.$3$. According to Lenz's Law, the induced current in the ring will oppose this increase in magnetic flux.$4$. The magnetic field lines from the wire point into the plane of the paper (using the right-hand thumb rule). Since the flux into the plane is increasing, the induced current must create a magnetic field pointing out of the plane to oppose this change.$5$. By the right-hand grip rule, a current that produces a magnetic field pointing out of the plane must be in the counter-clockwise (anticlockwise) direction.

$A$ conducting ring of certain resistance is falling towards a current-carrying straight long conductor. The ring and conductor are in the same plane. Then

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