(C) According to the work-energy theorem,the work done by the retarding force $(F)$ is equal to the change in kinetic energy of the vehicle.$W = \Delt

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Both come to rest in the same distance

(C) According to the work-energy theorem,the work done by the retarding force $(F)$ is equal to the change in kinetic energy of the vehicle.$W = \Delta K.E.$Since the vehicles are brought to rest,the work done $W = F \times s$,where $s$ is the stopping distance.Therefore,$F \times s = K.E.$$s = \frac{K.E.}{F}$Since both the lorry and the car have the same initial kinetic energy $(K.E.)$ and are subjected to the same retarding force $(F)$,the stopping distance $(s)$ must be the same for both vehicles.

Class 11 Physics Work, Energy, Power and Collision Work Energy Theorem and Conservation of Mechanical Energy

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$A$ lorry and a car moving with the same kinetic energy $(K.E.)$ are brought to rest by applying the same retarding force. Then:

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A
Lorry will come to rest in a shorter distance
B
Car will come to rest in a shorter distance
C
Both come to rest in the same distance
D
None of the above

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Work, Energy, Power and Collision

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Work Energy Theorem and Conservation of Mechanical Energy

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$A$ lorry and a car moving with the same kinetic energy $(K.E.)$ are brought to rest by applying the same retarding force. Then:

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For a body of mass $1 \ kg$,the $U-x$ graph is shown in the figure. If the body is released from rest at $x = 2 \ m$,then its speed when it crosses $x = 5 \ m$ is:

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