Two bodies of unequal mass are moving in the same direction with equal kinetic energy. The two bodies are brought to rest by applying retarding force of same magnitude. How would the distance moved by them before coming to rest compare ?
Two bodies of unequal mass are moving in the same direction with equal kinetic energy. The two bodies are brought to rest by applying retarding force of same magnitude. How would the distance moved by them before coming to rest compare ?
According to work-energy theorem, $\Delta \mathrm{K}=\mathrm{W}$
$\therefore \Delta \mathrm{K}=\mathrm{F} d$
As $\mathrm{KE}$ of the bodies and retarding forces applied on them are same, therefore, both bodies will travel equal distances before coming to rest.
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