$A$ logic circuit provides the output $Y$ as per the following truth table:
$A$ $B$ $Y$ $0$ $0$ $1$ $0$ $1$ $0$ $1$ $0$ $1$ $1$ $1$ $0$
The expression for the output $Y$ is:
| $A$ | $B$ | $Y$ |
|---|---|---|
| $0$ | $0$ | $1$ |
| $0$ | $1$ | $0$ |
| $1$ | $0$ | $1$ |
| $1$ | $1$ | $0$ |
The expression for the output $Y$ is:
- A$A \cdot \bar{B} + \bar{A}$
- B$\bar{B}$
- C$B$
- D$A \cdot B + \bar{A}$
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In the given digital circuit,if the inputs are $A=1, B=1$ and $C=1$,then the values of $y_1$ and $y_2$ are respectively:
In the circuit,the logical value of $A = 1$ or $B = 1$ when the potential at $A$ or $B$ is $5 \, V$,and the logical value of $A = 0$ or $B = 0$ when the potential at $A$ or $B$ is $0 \, V$. The truth table of the given circuit will be:
DifficultJEE MAIN 2022
View SolutionThe truth table given below corresponds to which logic gate?
$A$ $B$ $X$ $0$ $0$ $0$ $0$ $1$ $1$ $1$ $0$ $1$ $1$ $1$ $1$
| $A$ | $B$ | $X$ |
|---|---|---|
| $0$ | $0$ | $0$ |
| $0$ | $1$ | $1$ |
| $1$ | $0$ | $1$ |
| $1$ | $1$ | $1$ |
Consider the following logic circuit. The output is $Y = 0$ when
Identify the logic gate represented by the given circuit.
Difficult
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