In the circuit,the logical value of A = 1 or | vedclass

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(A) In the given circuit,if either input $A$ or $B$ is at $0 \, V$ (logical $0$),the corresponding diode ($D_1$ or $D_2$) becomes forward-biased. This

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$A$$B$$Y$$0$$0$$0$$1$$0$$0$$0$$1$$0$$1$$1$$1$

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(A) In the given circuit,if either input $A$ or $B$ is at $0 \, V$ (logical $0$),the corresponding diode ($D_1$ or $D_2$) becomes forward-biased. This pulls the output potential $Y$ down to approximately $0 \, V$ (logical $0$).If both inputs $A$ and $B$ are at $5 \, V$ (logical $1$),both diodes are reverse-biased. No current flows through the diodes,and the output $Y$ is pulled up to $5 \, V$ (logical $1$) through the resistor $R$.This behavior corresponds to an $AND$ gate,where the output is $1$ only if both inputs are $1$. The truth table is:$A$$B$$Y$$0$$0$$0$$0$$1$$0$$1$$0$$0$$1$$1$$1$

In the circuit,the logical value of $A = 1$ or $B = 1$ when the potential at $A$ or $B$ is $5 \, V$,and the logical value of $A = 0$ or $B = 0$ when the potential at $A$ or $B$ is $0 \, V$. The truth table of the given circuit will be:

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$A$	$B$	$Y$
$0$	$0$	$0$
$1$	$0$	$0$
$0$	$1$	$0$
$1$	$1$	$0$