A liquid flows through a horizontal tube. The | vedclass

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(D) According to the equation of continuity,the volume of liquid flowing through the tube in unit time remains constant,i.e.,$A_1 v_1 = A_2 v_2$. Henc

Vedclass · Accepted Answer

All of the above.

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(D) According to the equation of continuity,the volume of liquid flowing through the tube in unit time remains constant,i.e.,$A_1 v_1 = A_2 v_2$. Hence,option $(a)$ is correct.According to Bernoulli's theorem for a horizontal tube,the total energy per unit mass is conserved,meaning $P_1 + \frac{1}{2}\rho v_1^2 = P_2 + \frac{1}{2}\rho v_2^2$. Thus,option $(b)$ is correct.Rearranging the Bernoulli equation: $P_1 - P_2 = \frac{1}{2}\rho (v_2^2 - v_1^2)$.Since the pressure difference is measured by the height difference $h$ in the vertical tubes,$P_1 - P_2 = h\rho g$.Equating these,$h\rho g = \frac{1}{2}\rho (v_2^2 - v_1^2)$,which simplifies to $v_2^2 - v_1^2 = 2gh$. Hence,option $(c)$ is correct.Since $(a)$,$(b)$,and $(c)$ are all correct,option $(d)$ is the correct answer.

$A$ liquid flows through a horizontal tube. The velocities of the liquid in the two sections,which have areas of cross-section $A_1$ and $A_2$,are $v_1$ and $v_2$ respectively. The difference in the levels of the liquid in the two vertical tubes is $h$.

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