The flow speeds of air on the lower and upper | vedclass

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Question

$\mathrm{P}_{1}+\frac{1}{2} \rho \mathrm{v}_{1}^{2}=\mathrm{P}_{2}+\frac{1}{2} \rho \mathrm{v}_{2}^{2}$

$\Delta \mathrm{P}=\frac{1}{2} \rho\left(\m

Vedclass · Accepted Answer

$\frac{3}{2}\rho {v^2}\,A$

Vedclass · Answer

$\mathrm{P}_{1}+\frac{1}{2} \rho \mathrm{v}_{1}^{2}=\mathrm{P}_{2}+\frac{1}{2} \rho \mathrm{v}_{2}^{2}$

$\Delta \mathrm{P}=\frac{1}{2} \rho\left(\mathrm{v}_{2}^{2}-\mathrm{v}_{1}^{2}\right)$

$\Delta \mathrm{P}=\frac{1}{2} \rho\left[(2 \mathrm{v})^{2}-\mathrm{v}^{2}\right]$

$\Delta \mathrm{P}=\frac{3}{2} \rho \mathrm{v}^{2}$

The flow speeds of air on the lower and upper surfaces of the wing of an aeroplane are $v$ and $2v$ respectively. The density of air is $\rho $ and surface area of wing is $A$ . The dynamic lift on the wing is

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