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(B) Let $AB$ be the ladder and $CA$ be the wall with the window at $A$. The wall and the ground form a right angle at $C$. Thus,$	riangle ABC$ is a r

Vedclass · Accepted Answer

$6.5$

Vedclass · Answer

(B) Let $AB$ be the ladder and $CA$ be the wall with the window at $A$. The wall and the ground form a right angle at $C$. Thus,$	riangle ABC$ is a right-angled triangle with $\angle C = 90^\circ$.Given: $BC = 2.5\, m$ (distance of the foot of the ladder from the wall) and $CA = 6\, m$ (height of the window from the ground).According to the Pythagoras Theorem,in a right-angled triangle,the square of the hypotenuse is equal to the sum of the squares of the other two sides:$AB^2 = BC^2 + CA^2$$AB^2 = (2.5)^2 + (6)^2$$AB^2 = 6.25 + 36$$AB^2 = 42.25$$AB = \sqrt{42.25}$$AB = 6.5\, m$Therefore,the length of the ladder is $6.5\, m$.

$A$ ladder is placed against a wall such that its foot is at a distance of $2.5\, m$ from the wall and its top reaches a window $6\, m$ above the ground. Find the length of the ladder in $m$.

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