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(A) According to Dalton's Law of Partial Pressures,the partial pressure of a gas is proportional to its mole fraction in the mixture.Given that the mo

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$0.5$

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(A) According to Dalton's Law of Partial Pressures,the partial pressure of a gas is proportional to its mole fraction in the mixture.Given that the moles of $CO$ and $N_2$ are equal,let $n_{CO} = n_{N_2} = n$.The mole fraction of $N_2$ is given by $x_{N_2} = \frac{n_{N_2}}{n_{CO} + n_{N_2}} = \frac{n}{n + n} = \frac{n}{2n} = 0.5$.The partial pressure of $N_2$ is calculated as $p_{N_2} = x_{N_2} 	imes P_{total}$.Given $P_{total} = 1 \ atm$,we have $p_{N_2} = 0.5 	imes 1 \ atm = 0.5 \ atm$.

$A$ gaseous mixture was prepared by taking equal moles of $CO$ and $N_2$. If the total pressure of the mixture was found to be $1 \ atm$,the partial pressure of the nitrogen $(N_2)$ in the mixture is ............ $atm$.

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