The rate of diffusion of SO_{2},CO_{2},PCl_{3 | vedclass

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(B) According to Graham's Law of diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$: $r \propt

Vedclass · Accepted Answer

$CO_{2} > SO_{2} > SO_{3} > PCl_{3}$

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(B) According to Graham's Law of diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$: $r \propto \frac{1}{\sqrt{M}}$.First,calculate the molar masses of the given compounds:$M(CO_{2}) = 12 + 2 	imes 16 = 44 \ g/mol$$M(SO_{2}) = 32 + 2 	imes 16 = 64 \ g/mol$$M(SO_{3}) = 32 + 3 	imes 16 = 80 \ g/mol$$M(PCl_{3}) = 31 + 3 	imes 35.5 = 31 + 106.5 = 137.5 \ g/mol$Since the rate of diffusion is inversely proportional to the square root of the molar mass,the order of the rate of diffusion will be the reverse of the order of their molar masses:$M(CO_{2}) Therefore,the rate of diffusion order is: $CO_{2} > SO_{2} > SO_{3} > PCl_{3}$.

The rate of diffusion of $SO_{2}$,$CO_{2}$,$PCl_{3}$ and $SO_{3}$ are in the following order:

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