The ratio of rates of diffusion of helium (He | vedclass

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Question

(A) According to Graham's Law of diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$: $r \propt

Vedclass · Accepted Answer

$1 : \sqrt{2}$

Vedclass · Answer

(A) According to Graham's Law of diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$: $r \propto \frac{1}{\sqrt{M}}$.Molecular mass of $H_2$ $(M_{H_2})$ = $2 \ g/mol$.Molecular mass of $He$ $(M_{He})$ = $4 \ g/mol$.$\frac{r_{He}}{r_{H_2}} = \sqrt{\frac{M_{H_2}}{M_{He}}} = \sqrt{\frac{2}{4}} = \sqrt{\frac{1}{2}} = \frac{1}{\sqrt{2}}$.Therefore,the ratio is $1 : \sqrt{2}$.

The ratio of rates of diffusion of helium $(He)$ to hydrogen $(H_2)$.

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