Assertion : Radioactive nuclei emit ${\beta ^ - }$ particles.
Reason : Electrons exist inside the nucleus
Assertion : Radioactive nuclei emit ${\beta ^ - }$ particles.
Reason : Electrons exist inside the nucleus
- [AIIMS 2003]
- A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
- B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
- C
If the Assertion is correct but Reason is incorrect.
- D
If both the Assertion and Reason are incorrect.
Similar Questions
The mass of a nucleus ${ }_Z^A X$ is less that the sum of the masses of $(A-Z)$ number of neutrons and $Z$ number of protons in the nucleus. The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass $M$ can break into two light nuclei of masses $m_1$ and $m_2$ only if $\left(m_1+m_2\right)M^{\prime}$. The masses of some neutral atoms are given in the table below:
${ }_1^1 H$
$1.007825 u$
${ }_2^1 H$
$2.014102 u$
${ }_3^1 H$
$3.016050 u$
${ }_2^4 He$
$4.002603 u$
${ }_3^6 Li$
$6.015123 u$
${ }_7^3 Li$
$7.016004 u$
${ }_70^30 Zn$
$69.925325 u$
${ }_{34}^{82} Se$
$81.916709 u$
${ }_{64}^{152} Gd$
$151.919803 u$
${ }_{206}^{82} Gd$
$205.974455 u$
${ }_{209}^{83} Bi$
$208.980388 u$
${ }_{84}^{210} Po$
$209.982876 u$
$1.$ The correct statement is:
$(A)$ The nucleus ${ }_3^6 Li$ can emit an alpha particle
$(B)$ The nucleus ${ }_{84}^{210} P_0$ can emit a proton
$(C)$ Deuteron and alpha particle can undergo complete fusion.
$(D)$ The nuclei ${ }_{30}^{70} Zn$ and ${ }_{34}^{82} Se$ can undergo complete fusion.
$2.$ The kinetic energy (in $keV$ ) of the alpha particle, when the nucleus ${ }_{84}^{210} P _0$ at rest undergoes alpha decay, is:
$(A)$ $5319$ $(B)$ $5422$ $(C)$ $5707$ $(D)$ $5818$
Give the answer question $1$ and $2.$
The mass of a nucleus ${ }_Z^A X$ is less that the sum of the masses of $(A-Z)$ number of neutrons and $Z$ number of protons in the nucleus. The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass $M$ can break into two light nuclei of masses $m_1$ and $m_2$ only if $\left(m_1+m_2\right)M^{\prime}$. The masses of some neutral atoms are given in the table below:
| ${ }_1^1 H$ | $1.007825 u$ | ${ }_2^1 H$ | $2.014102 u$ | ${ }_3^1 H$ | $3.016050 u$ | ${ }_2^4 He$ | $4.002603 u$ |
| ${ }_3^6 Li$ | $6.015123 u$ | ${ }_7^3 Li$ | $7.016004 u$ | ${ }_70^30 Zn$ | $69.925325 u$ | ${ }_{34}^{82} Se$ | $81.916709 u$ |
| ${ }_{64}^{152} Gd$ | $151.919803 u$ | ${ }_{206}^{82} Gd$ | $205.974455 u$ | ${ }_{209}^{83} Bi$ | $208.980388 u$ | ${ }_{84}^{210} Po$ | $209.982876 u$ |
$1.$ The correct statement is:
$(A)$ The nucleus ${ }_3^6 Li$ can emit an alpha particle
$(B)$ The nucleus ${ }_{84}^{210} P_0$ can emit a proton
$(C)$ Deuteron and alpha particle can undergo complete fusion.
$(D)$ The nuclei ${ }_{30}^{70} Zn$ and ${ }_{34}^{82} Se$ can undergo complete fusion.
$2.$ The kinetic energy (in $keV$ ) of the alpha particle, when the nucleus ${ }_{84}^{210} P _0$ at rest undergoes alpha decay, is:
$(A)$ $5319$ $(B)$ $5422$ $(C)$ $5707$ $(D)$ $5818$
Give the answer question $1$ and $2.$
- [IIT 2013]
A nucleus of an element ${}_{84}{X^{202}}$ emits an $\alpha $-particle first, $\beta $ -particle next and then a gamma photon. The final nucleus formed has an atomic number
A nucleus of an element ${}_{84}{X^{202}}$ emits an $\alpha $-particle first, $\beta $ -particle next and then a gamma photon. The final nucleus formed has an atomic number
Beta rays emitted by a radioactive material are
Beta rays emitted by a radioactive material are
Consider the following two statements
$A.$ Energy spectrum of $\alpha-$ particles emitted in radioactive decay is discrete
$B.$ Energy spectrum of $ \beta -$ particles emitted in radioactive decay is continuous
Consider the following two statements
$A.$ Energy spectrum of $\alpha-$ particles emitted in radioactive decay is discrete
$B.$ Energy spectrum of $ \beta -$ particles emitted in radioactive decay is continuous
In nuclear reaction $_2H{e^4}{ + _z}{X^A}{ \to _{z + 2}}{Y^{A + 3}} + A,\;A$ denotes
In nuclear reaction $_2H{e^4}{ + _z}{X^A}{ \to _{z + 2}}{Y^{A + 3}} + A,\;A$ denotes