A dip needle in a plane perpendicular to magnetic meridian will remain

A current carrying coil is placed with its axis perpendicular to $ N-S $ direction. Let horizontal component of earth's magnetic field be $H_o$ and magnetic field inside the loop is $H$. If a magnet is suspended inside the loop, it makes angle $\theta $ with $H$. Then $\theta $$=$

A telephone cable at a place has four long straight horizontal wires carrying a current of $1.0\; A$ in the same direction east to west. The earth's magnetic field at the place is $0.39 \;G ,$ and the angle of dip is $35^{\circ} .$ The magnetic declination is nearly zero. What are the resultant magnetic fields at points $4.0\; cm$ below and above the cable?

Name the elements of the earth’s magnetic field.

Two normal uniform magnetic field contain a magnetic needle making an angle $60°$  with $F$. Then the ratio of $\frac{F}{H}$ is

A compass needle whose magnetic moment is $60 \,amp × m^2$ pointing geographical north at a certain place, where the horizontal component of earth's magnetic field is $40\, \mu Wb/m^2$, experiences a torque $1.2 \times {10^{ - 3}}\,N \times m.$ What is the declination at this place......$^o$