A die is thrown, find the probability of following events: A number more than $6$ will appear,
A die is thrown, find the probability of following events: A number more than $6$ will appear,
The sample space of the given experiment is given by
$S=\{1,2,3,4,5,6\}$
Let $D$ be the event of the occurrence of a number greater than $6.$
Accordingly, $D=\overset{\lower0.5em\hbox{$\smash{\scriptscriptstyle\frown}$}}{I}$
$\therefore P(D)=\frac{\text { Number of outcomes favourable to } D}{\text { Total number of possible outcomes }}=\frac{n(D)}{n(S)}=\frac{0}{6}=0$
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