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(A) The sample space $S$ of the experiment of throwing a die is given by $S = \{1, 2, 3, 4, 5, 6\}$.Total number of possible outcomes $n(S) = 6$.Let $

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(A) The sample space $S$ of the experiment of throwing a die is given by $S = \{1, 2, 3, 4, 5, 6\}$.Total number of possible outcomes $n(S) = 6$.Let $D$ be the event of the occurrence of a number greater than $6$.Since there is no number greater than $6$ on a standard die,$D = \emptyset$.Therefore,the number of favorable outcomes $n(D) = 0$.The probability $P(D)$ is given by $P(D) = \frac{n(D)}{n(S)} = \frac{0}{6} = 0$.

$A$ die is thrown. Find the probability of the following event: $A$ number more than $6$ will appear.

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