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(B) The volume of the gas remains constant, so $V = 	ext{constant}$.According to Gay-Lussac's Law, $P \propto T$ for a constant volume.Since the temp

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$P_0A$

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(B) The volume of the gas remains constant, so $V = 	ext{constant}$.According to Gay-Lussac's Law, $P \propto T$ for a constant volume.Since the temperature is doubled $(T_0 	o 2T_0)$, the pressure of the gas will also be doubled.Thus, the new pressure $P = 2P_0$.Let $F$ be the tension in the wire. Considering the equilibrium of one piston, the forces acting on it are the gas pressure force $(PA)$ acting outwards, the atmospheric pressure force $(P_0A)$ acting inwards, and the tension $(F)$ acting inwards.Therefore, $F + P_0A = PA$.$F = (P - P_0)A = (2P_0 - P_0)A = P_0A$.

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