A cyclic process ABCA is shown in the PT diag | vedclass

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(D) In the given cyclic process $ABCA$ on the $PT$ diagram:$1$. From $A$ to $B$: The pressure $P$ is constant,so this is an isobaric process. In a $PV

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(D) In the given cyclic process $ABCA$ on the $PT$ diagram:$1$. From $A$ to $B$: The pressure $P$ is constant,so this is an isobaric process. In a $PV$ diagram,this is a horizontal line.$2$. From $B$ to $C$: The line passes through the origin,meaning $P \propto T$. From the ideal gas law $PV = nRT$,we have $P = (nR/V)T$. Since $P/T$ is constant,the volume $V$ must be constant. This is an isochoric process,represented by a vertical line in a $PV$ diagram.$3$. From $C$ to $A$: The temperature $T$ is constant,so this is an isothermal process. In a $PV$ diagram,this is represented by a rectangular hyperbola $(P \propto 1/V)$.Comparing these characteristics with the given options,the process $A \rightarrow B$ (isobaric),$B \rightarrow C$ (isochoric),and $C \rightarrow A$ (isothermal) corresponds to the graph shown in option $D$.

Column-$I$	Column-$II$
$(a)$ Heat engine	$(i)$ $\eta = \frac{Q_2}{Q_1 - Q_2}$
$(b)$ Heat pump	$(ii)$ $\eta = \frac{Q_1 - Q_2}{Q_1}$
	$(iii)$ $\eta = \frac{T_1 - T_2}{T_1}$

$A$ cyclic process $ABCA$ is shown in the $PT$ diagram. When presented on a $PV$ diagram,it would be:

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