A compound of a metal ion $M^{x+}$ $(Z = 24)$ has a spin only magnetic moment of $\sqrt {15}$ Bohr Magnetons. The number of unpaired electrons in the compound are

  • [AIIMS 2013]
  • A

    $2$

  • B

    $4$

  • C

    $5$

  • D

    $3$

Similar Questions

A first row transition metal with highest enthalpy of atomisation, upon reaction with oxygen at high temperature forms oxides of formula $\mathrm{M}_2 \mathrm{O}_{\mathrm{n}}$ (where $\mathrm{n}=3,4,5$ ). The 'spin-only' magnetic moment value of the amphoteric oxide from the above oxides is. . . . . . ..$\mathrm{BM}$ (near integer)

(Given atomic number: $\mathrm{Sc}: 21, \mathrm{Ti}: 22, \mathrm{~V}: 23$, $\mathrm{Cr}: 24, \mathrm{Mn}: 25, \mathrm{Fe}: 26, \mathrm{Co}: 27, \mathrm{Ni}: 28, \mathrm{Cu}: 29$, $\mathrm{Zn}: 30)$

  • [JEE MAIN 2024]

Chloro compound of vanadium has only spin magnetic moment of $1.73\,BM$ . This vanadium chloride has the formula :- (at no. of $V = 23$ )

The number of $d-$ electrons in $F{e^{2 + }}$ (at no. of $Fe = 26$) is not equal to that of the

Which one of the following does not correctly represent the correct order of the property indicated against it?

  • [AIPMT 2012]

Which of the following will be coloured ion :