Chloro compound of vanadium has only spin mag | vedclass

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Question

Magnetic moment $=\sqrt{ n ( n +2)}$

where $n =$ number of unpaired electrons

$\sqrt{ n ( n +2)}=1.73$

$	herefore n =1$

Electronic config

Vedclass · Accepted Answer

$VCl_4$

Vedclass · Answer

Magnetic moment $=\sqrt{ n ( n +2)}$

where $n =$ number of unpaired electrons

$\sqrt{ n ( n +2)}=1.73$

$	herefore n =1$

Electronic configuration of $V$ is $[ Ar ] 4 s ^2 3 d ^3$. For only one unpaired electron it has to be $V ^{4+}$.

Hence, the formula of vanadium chloride is $V Cl _4$.

Chloro compound of vanadium has only spin magnetic moment of $1.73\,BM$ . This vanadium chloride has the formula :- (at no. of $V = 23$ )

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