A committee consists of 9 experts taken from | vedclass

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(d) Required probability $ = \frac{{{}^2{C_1} 	imes {}^3{C_1} 	imes {}^4{C_1}}}{{{}^9{C_3}}} $

$= \frac{{2 	imes 3 	imes 4}}{{\left( {\frac{{9

Vedclass · Accepted Answer

$\frac{2}{7}$

Vedclass · Answer

(d) Required probability $ = \frac{{{}^2{C_1} 	imes {}^3{C_1} 	imes {}^4{C_1}}}{{{}^9{C_3}}} $

$= \frac{{2 	imes 3 	imes 4}}{{\left( {\frac{{9 	imes 8 	imes 7}}{{3 	imes 2}}} ight)}} = \frac{2}{7}$.

A committee consists of $9$ experts taken from three institutions $A, B$ and $C$, of which $2$ are from $A, 3$ from $B$ and $4$ from $C$. If three experts resign, then the probability that they belong to different institutions is

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