Seven balls are drawn simultaneously from a bag containing $5$ white and $6$ green balls. The probability of drawing $3$ white and $4$ green balls is:

• A
  $\frac{7}{{ }^{11}C_7}$
• B
  $\frac{{ }^5C_3 + { }^6C_4}{{ }^{11}C_7}$
• C
  $\frac{{ }^5C_3 \times { }^6C_4}{{ }^{11}C_7}$
• D
  $\frac{{ }^6C_3 \times { }^5C_4}{{ }^{11}C_7}$