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(C) The colourless crystalline salt $X$ is $MgSO_4$. It is soluble in dilute $HCl$.When $NaOH$ solution is added to a solution of $MgSO_4$,it forms a

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$MgSO_4$

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(C) The colourless crystalline salt $X$ is $MgSO_4$. It is soluble in dilute $HCl$.When $NaOH$ solution is added to a solution of $MgSO_4$,it forms a white precipitate of magnesium hydroxide,$Mg(OH)_2$,which is insoluble in excess $NaOH$.$MgSO_4 + 2NaOH \rightarrow Mg(OH)_2 \downarrow + Na_2SO_4$In contrast,$Al^{3+}$,$Zn^{2+}$,and $Sn^{2+}$ salts form precipitates that are soluble in excess $NaOH$ due to the formation of soluble complex ions like $[Al(OH)_4]^-$,$[Zn(OH)_4]^{2-}$,or $[Sn(OH)_4]^{2-}$.

List-$I$ (Metal Ion)	List-$II$ (Group in Qualitative analysis)
$(a)$ $Mn^{2+}$	$(i)$ Group-$III$
$(b)$ $As^{3+}$	$(ii)$ Group-$IIA$
$(c)$ $Cu^{2+}$	$(iii)$ Group-$IV$
$(d)$ $Al^{3+}$	$(iv)$ Group-$IIB$

$A$ colourless crystalline salt $X$ is soluble in dilute $HCl$. On adding $NaOH$ solution,it gives a white precipitate which is insoluble in excess of $NaOH$. $X$ is

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