Match List-I with List-II : List-I (Meta | vedclass

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(B) In qualitative analysis,metal ions are classified into groups based on their precipitation reactions:$Mn^{2+}$ belongs to Group-$IV$ (precipitated

Vedclass · Accepted Answer

$(a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)$

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(B) In qualitative analysis,metal ions are classified into groups based on their precipitation reactions:$Mn^{2+}$ belongs to Group-$IV$ (precipitated as sulfide in alkaline medium).$As^{3+}$ belongs to Group-$IIB$ (precipitated as sulfide in acidic medium).$Cu^{2+}$ belongs to Group-$IIA$ (precipitated as sulfide in acidic medium).$Al^{3+}$ belongs to Group-$III$ (precipitated as hydroxide in the presence of $NH_4Cl$ and $NH_4OH$).Therefore,the correct matching is: $(a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)$.

List-$I$ (Metal Ion)	List-$II$ (Group in Qualitative analysis)
$(a)$ $Mn^{2+}$	$(i)$ Group-$III$
$(b)$ $As^{3+}$	$(ii)$ Group-$IIA$
$(c)$ $Cu^{2+}$	$(iii)$ Group-$IV$
$(d)$ $Al^{3+}$	$(iv)$ Group-$IIB$

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Match List-$I$ with List-$II$ : List-$I$ (Metal Ion) List-$II$ (Group in Qualitative analysis) $(a)$ $Mn^{2+}$ $(i)$ Group-$III$ $(b)$ $As^{3+}$ $(ii)$ Group-$IIA$ $(c)$ $Cu^{2+}$ $(iii)$ Group-$IV$ $(d)$ $Al^{3+}$ $(iv)$ Group-$IIB$ Choose the most appropriate answer from the options given below :