A coil having $N$ $turns$ carry a current $I$ as shown in the figure. The magnetic field intensity at point $P$ is
$\frac{{{\mu _0}NI{R^2}}}{{2{{({R^2} + {x^2})}^{3/2}}}}$
$\frac{{{\mu _0}NI}}{{2R}}$
$\frac{{{\mu _0}NI{R^2}}}{{{{(R + x)}^2}}}$
Zero
The ratio of the magnetic field at the centre of a current carrying coil of the radius $a$ and at a distance ‘$a$’ from centre of the coil and perpendicular to the axis of coil is
The magnetic field at the origin due to the current flowing in the wire is -
The radius of a circular current carrying coil is $R$. At what distance from the centre of the coil on its axis, the intensity of magnetic field will be $\frac{1}{2 \sqrt{2}}$ times that at the centre?
the magnetic induction at $O$ due to the whole length of the conductor is
Assertion : The magnetic field at the centre of the circular coil in the following figure due to the currents $I_1$ and $I_2$ is zero.
Reason : $I_1 = I_2$ implies that the fields due to the current $I_1$ and $I_2$ will be balanced.