Due to 10, ampere of current flowing in a cir | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c) $B = \frac{{{\mu _0}}}{{4\pi }} \cdot \frac{{2\pi Ni}}{r}$
$==>$ $3.14 	imes {10^{ - 3}} = \frac{{{{10}^{ - 7}} 	imes 2 	imes 3.14 	imes N

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(c) $B = \frac{{{\mu _0}}}{{4\pi }} \cdot \frac{{2\pi Ni}}{r}$
$==>$ $3.14 	imes {10^{ - 3}} = \frac{{{{10}^{ - 7}} 	imes 2 	imes 3.14 	imes N 	imes 10}}{{(10 	imes {{10}^{ - 2}})}}$ $==>$ $N = 50$

Due to $10\, ampere$ of current flowing in a circular coil of $10\, cm$ radius, the magnetic field produced at its centre is $3.14 \times {10^{ - 3}}\,Weber/{m^2}$. The number of turns in the coil will be

Similar Questions

$AB$ and $CD$ are long straight conductor, distance $d$ apart, carrying a current $I$. The magnetic field at the midpoint of $BC$ is

Find magnetic field at point $P$ in given diagram.

A current $i$ ampere flows in a circular arc of wire whose radius is $R$, which subtend an angle $3\pi /2$ radian at its centre. The magnetic induction at the centre is

The magnetic induction at a point $P$ which is distant $4\, cm$ from a long current carrying wire is ${10^{ - 8}}\,Tesla$. The field of induction at a distance $12\, cm $ from the same current would be

At what distance for a long straight wire carrying a current of $12\, A$ will the magnetic field be equal to $3 \times 10^{-5} Wb / m ^{2}$ ?