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(B) The circumference of the circular wire with radius $r_1 = 7\,cm$ is given by $L = 2\pi r_1 = 2 	imes \pi 	imes 7 = 14\pi\,cm$.This wire is bent

Vedclass · Accepted Answer

$210$

Vedclass · Answer

(B) The circumference of the circular wire with radius $r_1 = 7\,cm$ is given by $L = 2\pi r_1 = 2 	imes \pi 	imes 7 = 14\pi\,cm$.This wire is bent into an arc of a circle with radius $r_2 = 12\,cm$. The length of the arc is $L = 14\pi\,cm$.The formula for the angle $	heta$ subtended by an arc at the centre is $	heta = \frac{L}{r_2}$ (in radians).$	heta = \frac{14\pi}{12} = \frac{7\pi}{6}$ radians.To convert radians to degrees,multiply by $\frac{180^o}{\pi}$:$	heta = \frac{7\pi}{6} 	imes \frac{180^o}{\pi} = 7 	imes 30^o = 210^o$.

$A$ circular wire of radius $7\,cm$ is cut and bent again into an arc of a circle of radius $12\,cm$. The angle subtended by the arc at the centre is ......$^o$

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