A charged particle carrying charge $1\,\mu C$ is moving with velocity $(2 \hat{ i }+3 \hat{ j }+4 \hat{ k })\, ms ^{-1} .$ If an external magnetic field of $(5 \hat{ i }+3 \hat{ j }-6 \hat{ k }) \times 10^{-3}\, T$ exists in the region where the particle is moving then the force on the particle is $\overline{ F } \times 10^{-9} N$. The vector $\overrightarrow{ F }$ is :
$-0.30 \hat{ i }+0.32 \hat{ j }-0.09 \hat{ k }$
$-300 \hat{ i }+320 \hat{ j }-90 \hat{ k }$
$-30 \hat{ i }+32 \hat{ j }-9 \hat{ k }$
$-3.0 \hat{ i }+3.2 \hat{ j }-0.9 \hat{ k }$
Electron of mass $m$ and charge $q$ is travelling with a speed along a circular path of radius $r$ at right angles to a uniform magnetic field of intensity $B$. If the speed of the electron is doubled and the magnetic field is halved the resulting path would have a radius
An electron is projected normally from the surface of a sphere with speed $v_0$ in a uniform magnetic field perpendicular to the plane of the paper such that its strikes symmetrically opposite on the sphere with respect to the $x-$ axis. Radius of the sphere is $'a'$ and the distance of its centre from the wall is $'b'$ . What should be magnetic field such that the charge particle just escapes the wall
The radius of curvature of the path of a charged particle moving in a static uniform magnetic field is
At a specific instant emission of radioactive compound is deflected in a magnetic field. The compound can emit
$(i)$ Electrons $(ii)$ Protons $(iii)$ $H{e^{2 + }}$ $(iv)$ Neutrons
The emission at the instant can be
$\alpha $ particle, proton and duetron enters in a uniform (transverse) magnetic field $'B'$ with same acceleration potential find ratio of radius of path followed by these particles.