A certain radioactive material _ZX^A starts e | vedclass

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Question

Let there be $x$ $\alpha$ -particles and $y$ $\beta$ -particles

${\,_Z}{X^A} 	o xHe_2^4 + y\beta _{ - 1}^0 + Y_{z - 3}^{A - 8}$

then equating t

Vedclass · Accepted Answer

$1$ and $2$ respectively

Vedclass · Answer

Let there be $x$ $\alpha$ -particles and $y$ $\beta$ -particles

${\,_Z}{X^A} 	o xHe_2^4 + y\beta _{ - 1}^0 + Y_{z - 3}^{A - 8}$

then equating the mass numbers

$A=4 x+A-8$             .......$(i)$

and equating atomic number

$Z=2 x-y+Z-3$                .......$(ii)$

Solving eqns. $(i)$ and $(iii),$ we get:

$x=2$ and $y=1$

$	herefore $ The number of $\alpha$ and $\beta$ particles emitted are $2$ and $1$ respectively.

A certain radioactive material $_ZX^A$ starts emitting $\alpha $ and $\beta $ particles successively such that the end product is $_{Z-3}Y^{A-8}$. The number of $\beta $ and $\alpha $ particles emitted are

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