A certain radioactive material _ZX^A starts e | vedclass

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Question

(D) Let the number of $\alpha$-particles emitted be $x$ and the number of $\beta$-particles emitted be $y$.The decay equation is: $_ZX^A 	o x(_2He^4)

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$1$ and $2$ respectively

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(D) Let the number of $\alpha$-particles emitted be $x$ and the number of $\beta$-particles emitted be $y$.The decay equation is: $_ZX^A 	o x(_2He^4) + y(_{-1}\beta^0) + _{Z-3}Y^{A-8}$.Equating the mass numbers on both sides:$A = 4x + 0y + (A - 8)$$4x = 8 \implies x = 2$.Equating the atomic numbers on both sides:$Z = 2x - y + (Z - 3)$$0 = 2x - y - 3$Substituting $x = 2$:$0 = 2(2) - y - 3$$0 = 4 - y - 3$$y = 1$.Thus,the number of $\alpha$-particles emitted is $2$ and the number of $\beta$-particles emitted is $1$. The question asks for the number of $\beta$ and $\alpha$ particles respectively,which is $1$ and $2$.

$A$ certain radioactive material $_ZX^A$ starts emitting $\alpha$ and $\beta$ particles successively such that the end product is $_{Z-3}Y^{A-8}$. The number of $\beta$ and $\alpha$ particles emitted are

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